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Proof step 8 from proof sep-inj2-imp (previous step)

P0(H1), P2(H0), H1 ⊥ H0, ∀ H. P0(H) → P1(H), ∀ H. P2(H) → P3(H) ⊦ ((P1 * P3))(H1 ∪ H0), P1(H1) ∧ P3(H0) ∧ H1 ⊥ H0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information