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Proof step 2 from proof sep-inj3 (
previous step
)
P0 = P1, P2 = P3, P4 = P5 ⊦ P0 * P2 * P4 = P1 * P3 * P5
Heuristic simplifier applied rule simplifier
And closed the goal!
Rule argument
Additional information
Used simplifier rules: sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2;%sep-com: ⊦ P0 * P1 = P1 * P0;