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Proof step 11 from proof sep-mp-p (previous step)

((P0 * (P0 -* P1)))(H1), P2(H0), H1 ⊥ H0 ⊦ ((P1 * P2))(H1 ∪ H0), P1(H1)

User applied rule apply lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: sep-mp seq: ⊦ ((P0 * (P0 -* P1)))(H) → P1(H) subst: [P0, P1, H] → [P0, P1, H1]

Additional information

Used terms: P0, P1, H1