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Proof step 14 from proof sep-partial-mp (previous step)

P0(H2), P2(H0), H0 ⊥ H1, H0 ⊥ H2, H2 ⊥ H1, H2 ⊥ H0, (H1 ⊥ H2 ∧ H1 ⊥ H0) ∧ ((P0 * P2))(H2 ∪ H0) → P1((H2 ∪ H0) ∪ H1) ⊦ P1(H0 ∪ H2 ∪ H1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
P0(H2), P2(H0), H2 ⊥ H1, H0 ⊥ H2, H0 ⊥ H1, ((P0 * P2))(H2 ∪ H0) → P1((H2 ∪ H0) ∪ H1) ⊦ P1(H0 ∪ H2 ∪ H1)

Rule argument

Additional information

Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s)