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Proof step 18 from proof sep-partial-mp (previous step)

P0(H2), P1((H2 ∪ H0) ∪ H1), P2(H0), H0 ⊥ H1, H0 ⊥ H2, H2 ⊥ H1 ⊦ P1(H0 ∪ H2 ∪ H1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1
Proof step 20:
P0(H2), P1((H0 ∪ H2) ∪ H1), P2(H0), H2 ⊥ H1, H0 ⊥ H1, H0 ⊥ H2 ⊦ P1(H0 ∪ H2 ∪ H1)

Rule argument

spec: heap name: uni-com seq: ⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1 subst: [H0, H1] → [H0, H2] flags: <all paths>

Additional information

Used terms: H0, H2