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Proof step 3 from proof septract-dual (previous step)

⊦ ((P0 -* P1))(H) ↔ ¬ ((P0 -⊗ ¬ P1))(H)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ ((P0 -* P1))(H) ↔ (∀ H1. H1 ⊥ H ∧ P0(H1) → P1(H1 ∪ H))
Proof step 5:
⊦ (∀ H1. H1 ⊥ H ∧ P0(H1) → P1(H1 ∪ H)) ↔ ¬ ((P0 -⊗ ¬ P1))(H)

Rule argument

spec: <toplevel> name: wand seq: ⊦ ((P0 -* P1))(H) ↔ (∀ H1. H1 ⊥ H ∧ P0(H1) → P1(H1 ∪ H)) subst: [H, P1, P0] → [H, P1, P0] flags: <all paths>

Additional information

Used terms: H, P1, P0