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Proof step 2 from proof septract-given (previous step)

precise(P0) ⊦ P0 -⊗ P0 * P1 ⊆ P1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
((P0 -⊗ P0 * P1))(H), precise(P0) ⊦ P1(H)

Rule argument

Additional information

Used simplifier rules: Imp: ⊦ P0 ⊆ P1 ↔ (∀ H. P0(H) → P1(H));