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Proof step 5 from proof septract-given (
previous step
)
precise(P0), ∃ H0, H1. H0 ⊥ H ∧ H1 = H0 ∪ H ∧ P0(H0) ∧ ((P0 * P1))(H1) ⊦ P1(H)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
((P0 * P1))(H1 ∪ H), P0(H1), precise(P0), H1 ⊥ H ⊦ P1(H)
Rule argument
Additional information