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Proof step 7 from proof sharing-emp (previous step)

H1 ∪ H0 = ∅, P(H2 ∪ H0), H1 ⊥ H0, H2 ⊥ H1, H2 ⊥ H0 ⊦ P(H2)

User applied rule cut formula

And obtained the following new goals

Proof step 8:
H1 ∪ H0 = ∅, P(H2 ∪ H0), H2 ⊥ H0, H2 ⊥ H1, H1 ⊥ H0 ⊦ P(H2), H1 = ∅ ∧ H0 = ∅

Rule argument

fma: H1 = ∅ ∧ H0 = ∅

Additional information

Used simplifier rules: ⊦ ∅ ∪ H = H; (s)% ⊦ ∅ ⊥ H; (s)% ⊦ H ⊥ ∅; (s)% ⊦ H ∪ ∅ = H; (s) Used formulas: H1 = ∅ ∧ H0 = ∅