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Proof step 1 from proof split-union (conclusion)
⊦ P0(H0) ∧ P1(H1) ∧ H0 ⊥ H1 → ((P0 * P1))(H0 ∪ H1)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
P0(H0), P1(H1), H0 ⊥ H1 ⊦ ((P0 * P1))(H0 ∪ H1)
Rule argument
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