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Proof step 14 from proof stability (previous step)

⊦ ((P0 -⊗ P1))(H) ↔ (∃ H0, H1. H0 ⊥ H ∧ H1 = H0 ∪ H ∧ P0(H0) ∧ P1(H1))

Lemma septract