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Proof step 15 from proof stability (previous step)

((P0 * {H2} ))(H0), P(H0), P1(H3), H3 ⊥ H2 ⊦ ((P1 * (P0 -⊗ P)))(H3 ∪ H2), P(H3 ∪ H2), ∃ H0, H1. H0 ⊥ H2 ∧ H1 = H0 ∪ H2 ∧ P0(H0) ∧ P(H1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information