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Proof step 19 from proof stability (previous step)

P(H1 ∪ H), P0(H1), P1(H3), H1 ⊥ H, H3 ⊥ H ⊦ ((P1 * (P0 -⊗ P)))(H3 ∪ H), P(H3 ∪ H), ∃ H0. H0 ⊥ H ∧ P0(H0) ∧ P(H0 ∪ H)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: H1

Additional information

Used terms: H1