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Proof step 7 from proof stability (previous step)

((P0 * {H} ))(H0), P(H0), ∃ H0, H2. H0 ⊥ H2 ∧ H1 = H0 ∪ H2 ∧ P1(H0) ∧ {H} (H2) ⊦ (((P0 -⊗ P) * P1))(H1), P(H1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
((P0 * {H2} ))(H0), P(H0), P1(H3), H3 ⊥ H2 ⊦ (((P0 -⊗ P) * P1))(H3 ∪ H2), P(H3 ∪ H2)

Rule argument

Additional information

Used simplifier rules: this: ⊦ {H} (H0) ↔ H = H0;