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Proof step 6 from proof true-elim (previous step)

P(H0), P0(H1), H1 ⊥ H0 ⊦ ((true * P))(H1 ∪ H0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ P0(H0) ∧ P1(H1) ∧ H0 ⊥ H1 → ((P0 * P1))(H0 ∪ H1)

Rule argument

spec: <toplevel> name: split-union seq: ⊦ P0(H0) ∧ P1(H1) ∧ H0 ⊥ H1 → ((P0 * P1))(H0 ∪ H1) subst: [H1, H0, P1, P0] → [H0, H1, P, true] flags: <all paths>

Additional information

Used simplifier rules: trueH: ⊦ true(H); Used terms: H0, H1, P, true