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Proof step 34 from proof wand-flatten (previous step)

P0(H0), P1(H1), H0 ⊥ H, H1 ⊥ H0, H1 ⊥ H, H1 ∪ H0 ⊥ H ∧ ((P0 * P1))(H1 ∪ H0) → P2((H1 ∪ H0) ∪ H) ⊦ P2(H1 ∪ H0 ∪ H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
P0(H0), P1(H1), P2((H1 ∪ H0) ∪ H), H0 ⊥ H, H1 ⊥ H0, H1 ⊥ H ⊦ P2(H1 ∪ H0 ∪ H)

Rule argument

Additional information

Used simplifier rules: split-union: ⊦ P0(H0) ∧ P1(H1) ∧ H0 ⊥ H1 → ((P0 * P1))(H0 ∪ H1);%sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2;%sep-com: ⊦ P0 * P1 = P1 * P0;% ⊦ H1 ⊥ H2 → (H1 ∪ H2 ⊥ H0 ↔ H0 ⊥ H1 ∧ H0 ⊥ H2); (ws)% ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s)% ⊦ H1 ⊥ H2 → (H1 ∪ H2 ⊥ H0 ↔ H0 ⊥ H1 ∧ H0 ⊥ H2); (ss)