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Proof step 7 from proof wand-shift-p (
previous step
)
∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ ((P0 * (P1 -* P2)))(H0) ∧ P(H1) ⊦ (((P1 -* P0 * P2) * P))(H)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 8
:
((P0 * (P1 -* P2)))(H1), P(H0), H1 ⊥ H0 ⊦ (((P1 -* P0 * P2) * P))(H1 ∪ H0)
Rule argument
Additional information