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Proof step 17 from proof wand-shift (previous step)

P0(H1), P1(H), P2(H ∪ H0), H1 ⊥ H0, H ⊥ H1, H ⊥ H0 ⊦ H ∪ H1 ∪ H0 = H1 ∪ H ∪ H0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ H0 ⊥ H1 ∧ H1 ⊥ H ∧ H ⊥ H0 → (H0 ∪ H1) ∪ H = H0 ∪ H1 ∪ H
Proof step 19:
P0(H1), P1(H), P2(H ∪ H0), H ⊥ H0, H ⊥ H1, H1 ⊥ H0, H0 ⊥ H ⊦ (H ∪ H1) ∪ H0 = H1 ∪ H ∪ H0

Rule argument

spec: heap name: uni-ass seq: ⊦ H0 ⊥ H1 ∧ H1 ⊥ H ∧ H ⊥ H0 → (H0 ∪ H1) ∪ H = H0 ∪ H1 ∪ H subst: [H, H1, H0] → [H0, H1, H] flags: <rotated> <all paths>

Additional information

Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s) Used terms: H0, H1, H