[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 1 from proof at-uni (conclusion)
r ∈ H0 ∪ H1 ⊦ H0 ⊥ H1 → (H0 ∪ H1)[r] = (r ∈ H0 ⊃ H0[r];H1[r])
System applied rule normalize
And obtained the following new goals
Proof step 2
:
r ∈ H0 ∪ H1, H0 ⊥ H1 ⊦ (H0 ∪ H1)[r] = (r ∈ H0 ⊃ H0[r];H1[r])
Rule argument
Additional information