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Proof step 6 from proof del-notin (previous step)

r0 ∈ H ⊦ (H -- r)[r0] = H[r0], r ∈ H

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
r ∈ H ⊦ r ≠ r0 → (H -- r0)[r] = H[r]

Rule argument

spec: <toplevel> name: at-del seq: r ∈ H ⊦ r ≠ r0 → (H -- r0)[r] = H[r] subst: [r, r0, H] → [r0, r, H] flags: <all paths>

Additional information

Used terms: r0, r, H