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Proof step 24 from proof del-uni (previous step)

H0 ⊥ H1 ⊦ r0 ≠ r ∧ (r0 ∈ H0 ∨ r0 ∈ H1) ↔ r0 ∈ (H0 -- r) ∪ (H1 -- r), H0 -- r ⊥ H1 -- r

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information