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Proof step 14 from proof disj-distr-uni (previous step)

r0 ∈ H0, r0 ∈ H, H1 ⊥ H, ∀ r. ¬ r ∈ H0 ∨ ¬ r ∈ H1 ∧ ¬ r ∈ H ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: r0

Additional information

Used simplifier rules: disj-r: ⊦ r ∈ H1 ∧ H0 ⊥ H1 → (r ∈ H0 ↔ false); Used terms: r0