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Proof step 8 from proof disj-distr-uni (previous step)

H1 ⊥ H, ∀ r. ¬ r ∈ H0 ∨ ¬ r ∈ H1 ∧ ¬ r ∈ H ⊦ (∀ r. ¬ r ∈ H0 ∨ ¬ r ∈ H1) ∧ H0 ⊥ H

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information