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Proof step 4 from proof exin-uni (previous step)

r ∈ H ⊦ r = null, ∃ H0, o. H = H0 ∪ (∅ ++ r)[r, o] ∧ ¬ r ∈ H0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
r ∈ H ⊦ ∃ H0, o. H = H0 ∪ (∅ ++ r)[r, o] ∧ ¬ r ∈ H0

Rule argument

Additional information

Used simplifier rules: nonnull: ⊦ r ∈ H → r ≠ null;