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Proof step 9 from proof exin-uni (
previous step
)
⊦ r = null, r ∈ H0, (H0 ++ r)[r, o] = H0 ∪ (∅ ++ r)[r, o] ∧ ¬ r ∈ H0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 10
:
⊦ (H0 ++ r)[r, o] = H0 ∪ (∅ ++ r)[r, o], r = null, r ∈ H0
Rule argument
Additional information