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Proof step 3 from proof size-uni (previous step)

H0 ⊥ H1 ⊦ #(H0 ∪ H1) = # H0 + # H1

User applied rule induction

And obtained the following new goals

Proof step 4:
H0 ⊥ H1, ∀ H, H0. # H < # H1 → H0 ⊥ H → #(H0 ∪ H) = # H0 + # H ⊦ #(H0 ∪ H1) = # H0 + # H1

Rule argument

indvar: # H1 wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # H1