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Proof step 2 from proof subset-at (
previous step
)
r ∈ H0, H0 ⊆ H1 ⊦ H1[r] = H0[r]
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
r ∈ H0, H0 ⊆ H1 ⊦ H1[r] = H0[r]
Rule argument
Additional information