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Proof step 5 from proof subset-at (
previous step
)
r ∈ H0, ∀ r. (r ∈ H0 → r ∈ H1) ∧ (r ∈ H0 → H0[r] = H1[r]) ⊦ H1[r] = H0[r]
User applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: r abort: F discard: F computed: T
Additional information
Used terms: r