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Proof step 1 from proof subset-uni (conclusion)

⊦ H0 ⊆ H1 ↔ (∃ H. H0 ∪ H = H1 ∧ H ⊥ H0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ H0 ⊆ H1 ↔ (∃ H. H ∪ H0 = H1 ∧ H ⊥ H0)

Rule argument

Additional information

Used simplifier rules: uni-com: ⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1;