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Proof step 5 from proof subset-uni (
previous step
)
H0 ⊆ H1, H1 \ H0 ⊥ H0 ⊦ (H1 \ H0) ∪ H0 = H1 ∧ H1 \ H0 ⊥ H0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
H0 ⊆ H1, H1 \ H0 ⊥ H0 ⊦ (H1 \ H0) ∪ H0 = H1
Rule argument
Additional information