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Proof step 6 from proof sw-alloc-put (previous step)

r1 ∈ H, r = r0 ∨ r ∈ H ⊦ (r = r1 ⊃ o1;(r = r0 ⊃ o0;(H ++ r0)[r])) = (r = r0 ⊃ o0;(H[r1, o1] ++ r0)[r]), r0 = null, r0 ∈ H

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 7:
r1 ∈ H, r = r0 ∨ r ∈ H ⊦ (r = r1 ⊃ o1;(r = r0 ⊃ o0;(H ++ r0)[r])) = (r = r0 ⊃ o0;(H[r1, o1] ++ r0)[r]), r = r0, r0 = null, r0 ∈ H

Rule argument

fma: r = r0

Additional information

Used formulas: r = r0