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Proof step 14 from proof sw-del-add-new (previous step)

r0 ∈ H ⊦ (H ++ r)[r0] = H[r0], r = null, r0 ∈ rs, r ∈ H, r ∈ rs

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: at-alloc seq: r ∈ H, r0 ≠ null, ¬ r0 ∈ H ⊦ r ≠ r0 → (H ++ r0)[r] = H[r] subst: [r, r0, H] → [r0, r, H] flags: <all paths>

Additional information

Used terms: r0, r, H