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Proof step 17 from proof sw-del-add (
previous step
)
r1 ∈ H ⊦ H[r1] = (H ++ r)[r1], r = null, r0 = r, r1 = r0, r ∈ H
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 18
:
r ∈ H, r0 ≠ null, ¬ r0 ∈ H ⊦ r ≠ r0 → (H ++ r0)[r] = H[r]
Rule argument
spec: <toplevel> name: at-alloc seq: r ∈ H, r0 ≠ null, ¬ r0 ∈ H ⊦ r ≠ r0 → (H ++ r0)[r] = H[r] subst: [r, r0, H] → [r1, r, H] flags: <all paths>
Additional information
Used terms: r1, r, H