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Proof step 8 from proof sw-delswr (
previous step
)
r ∈ H, ∀ r, H, o. r ∈ H → H[r, o] \ rs0 = (H \ rs0)[r, o] ∨ r ∈ rs0 ⊦ (H -- r0)[r, o] \ rs0 = ((H -- r0) \ rs0)[r, o], r = r0, r ∈ rs0
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: r, H -- r0, o
Additional information
Used simplifier rules: in-del: ⊦ r ∈ H -- r0 ↔ r ≠ r0 ∧ r ∈ H; Used terms: r, H -- r0, o