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Proof step 5 from proof write-left (previous step)

r ∈ H0, H0 ⊥ H1 ⊦ (H0 ∪ H1)[r, o] = H0[r, o] ∪ H1, H1 ⊥ H0[r, o]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
r ∈ H0, H0 ⊥ H1 ⊦ (H0 ∪ H1)[r, o] = H0[r, o] ∪ H1, H1 ⊥ H0[r, o]

Rule argument

Additional information