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Proof step 8 from proof Sep-distribute-true (previous step)

∀ nP, n. nP ⊗_(n, m0) * true = (λ n0. nP(n0) * true)⊗_(n, m0) * true ⊦ (nP(n) * nP ⊗_(n + 1, m0)) * true = true * nP(n) * (λ n0. nP(n0) * true)⊗_(n + 1, m0)

User applied rule all left

And obtained the following new goals

Proof step 9:
nP ⊗_(n + 1, m0) * true = (λ n0. nP(n0) * true)⊗_(n + 1, m0) * true ⊦ (nP(n) * nP ⊗_(n + 1, m0)) * true = true * nP(n) * (λ n0. nP(n0) * true)⊗_(n + 1, m0)

Rule argument

pos: left 1 terms: nP, n + 1 abort: F discard: T computed: F

Additional information

Used terms: nP, n + 1