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Proof step 2 from proof Sep-emp (previous step)

∀ n. (λ n. emp)⊗_(n, m0) = emp ⊦ (λ n. emp)⊗_(n, m0 +1) = emp

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ n. (λ n. emp)⊗_(n, m0) = emp ⊦ (λ n. emp)⊗_(n, m0 + 1) = emp

Rule argument

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)