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Proof step 5 from proof Sep-emp (previous step)

∀ n. (λ n. emp)⊗_(n, m0) = emp ⊦ emp * (λ n. emp)⊗_(n + 1, m0) = emp

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
∀ n. (λ n. emp)⊗_(n, m0) = emp ⊦ (λ n. emp)⊗_(n + 1, m0) = emp

Rule argument

Additional information

Used simplifier rules: sep-com: ⊦ P0 * P1 = P1 * P0; from specification heap-sep%sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2; from specification heap-sep% ⊦ emp * P = P; (s)