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Proof step 6 from proof Sep-forall-reduce-imp (previous step)

((nP0 ⊗_(n, m) * P))(H), n0 < m, ∀ n0. n0 < m → nP0(n + n0) ⊆ nP1(n + n0) ⊦ ((nP1 ⊗_(n, m) * P))(H), nP0 ⊗_(n, m) ⊆ nP1 ⊗_(n, m), nP0(n + n0) ⊆ nP1(n + n0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n0

Additional information

Used terms: n0