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Proof step 13 from proof Sep-split (previous step)

nP ⊗_(n + 1, m + n0) = nP ⊗_(n + 1, m) * nP ⊗_((n + 1) + m, n0) ⊦ nP(n) * nP ⊗_(n + 1, m + n0) = (nP(n) * nP ⊗_(n + 1, m)) * nP ⊗_(n + m + 1, n0)

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2; from specification heap-sep%sep-com: ⊦ P0 * P1 = P1 * P0; from specification heap-sep