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Proof step 2 from proof Sep-split (previous step)

m0 ≤ m ⊦ nP ⊗_(n, m) = nP ⊗_(n, m0) * nP ⊗_(n + m0, m - m0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
m = n0 + m0, m0 ≤ m ⊦ nP ⊗_(n, m) = nP ⊗_(n, m0) * nP ⊗_(n + m0, n0)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m, m0, n0]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: m, m0, n0