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Proof step 2 from proof Sep-unfold (previous step)

m0 < m ⊦ nP ⊗_(n, m) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, m - m0 - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m0 < m ⊦ nP ⊗_(n, m) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, m - m0 - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic