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Proof step 9 from proof Sep-unfold (previous step)

m0 ≤ (m + 1) + m0 ⊦ nP ⊗_(n, m0) * nP ⊗_(n + m0, (m + 1) + m0 - m0) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
⊦ nP ⊗_(n, m0) * nP ⊗_(n + m0, m + 1) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, m)

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m + n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n - m = n; (s)