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Proof step 3 from proof Sep-weak-conjunction (
previous step
)
⊦ m0 < m → nP ⊗_(n, m) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, m - m0 - 1)
Lemma
Sep-unfold