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Proof step 2 from proof And-discard (previous step)

⊦ s = ∅, (λ a. P) ∧_ s = P

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ # s = 0, s = ∅, (λ a. P) ∧_ s = P

Rule argument

Additional information

Used simplifier rules: size-zero: ⊦ # s ≠ 0 → s ≠ ∅; (forward) from specification set-basic%size-zero-01: ⊦ s ≠ ∅ → # s ≠ 0; (forward) from specification set-basic