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Proof step 11 from proof precise-Sep (previous step)

a = a ∨ a ∈ s0 → precise(aP(a)), ∀ a0. a0 ∈ s0 → precise(aP(a0)), ∀ s1, aP. # s1 < #(s0 ++ a) → (∀ a. a ∈ s1 → precise(aP(a))) → precise(aP ⊗_ s1) ⊦ precise(aP(a) * aP ⊗_ s0), a ∈ s0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
precise(aP(a)), ∀ a0. a0 ∈ s0 → precise(aP(a0)), ∀ s1, aP. # s1 < #(s0 ++ a) → (∀ a. a ∈ s1 → precise(aP(a))) → precise(aP ⊗_ s1) ⊦ precise(aP(a) * aP ⊗_ s0), a ∈ s0

Proof step 11 from proof precise-Sep (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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