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Proof step 1 from proof Sep-forall (conclusion)

∀ a, H. a ∈ st ∧ adP0(a, st[a])(H) → adP(a, st[a])(H) ⊦ ((adP0 ⊗_ st))(H) → ((adP ⊗_ st))(H)

System applied rule normalize

And obtained the following new goals

Proof step 2:
((adP0 ⊗_ st))(H), ∀ a, H. a ∈ st ∧ adP0(a, st[a])(H) → adP(a, st[a])(H) ⊦ ((adP ⊗_ st))(H)

Rule argument

Additional information