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Proof step 19 from proof ex-lst-shift (
previous step
)
rs1 ∩ rs0 = ∅, R[rs0, cf, af], xv(x)(mk(rs1, cf)), ∀ r. r ∈ rs1 → af(r) = o ⊦ o[xv(x)](mk(rs1, cf, af)), (o[xv(x)] * R)[rs1 ∪ rs0, cf, af]
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 20
:
⊦ o[P](mk(rs, cf, af)) ↔ P(mk(rs, cf)) ∧ (∀ r. r ∈ rs → af(r) = o)
Rule argument
spec: embed-aux, inst: cell-heap-aux name: lift-aux seq: ⊦ o[P](mk(rs, cf, af)) ↔ P(mk(rs, cf)) ∧ (∀ r. r ∈ rs → af(r) = o) subst: [af, cf, rs, P, o] → [af, cf, rs1, xv(x), o] flags: <all paths>
Additional information
Used terms: af, cf, rs1, xv(x), o