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Proof step 32 from proof ex-lst-shift (previous step)

rs1 ∩ rs0 = ∅, R[rs0, cf, af], xv(x)(mk(rs1, cf)), ∀ r. r ∈ rs1 → af(r) = o ⊦ (o[_∃ xv] * R)[rs1 ∪ rs0, cf, af], o[_∃ xv][rs1, cf, af] ∧ R[rs0, cf, af] ∧ rs1 ∩ rs0 = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
rs1 ∩ rs0 = ∅, R[rs0, cf, af], xv(x)(mk(rs1, cf)), ∀ r. r ∈ rs1 → af(r) = o ⊦ (o[_∃ xv] * R)[rs1 ∪ rs0, cf, af], o[_∃ xv][rs1, cf, af]

Proof step 32 from proof ex-lst-shift (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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