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Proof step 37 from proof ex-lst-shift (previous step)

rs1 ∩ rs0 = ∅, R[rs0, cf, af], xv(x)(mk(rs1, cf)), ∀ r. r ∈ rs1 → af(r) = o ⊦ (o[_∃ xv] * R)[rs1 ∪ rs0, cf, af], (_∃ xv)(mk(rs1, cf)) ∧ (∀ r. r ∈ rs1 → af(r) = o)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
rs1 ∩ rs0 = ∅, R[rs0, cf, af], xv(x)(mk(rs1, cf)), ∀ r. r ∈ rs1 → af(r) = o ⊦ (o[_∃ xv] * R)[rs1 ∪ rs0, cf, af], (_∃ xv)(mk(rs1, cf))

Proof step 37 from proof ex-lst-shift (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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